Answer
The provided statement does not make any sense.
Work Step by Step
In an augmented matrix, any row can be deleted when every element in the row is zero.
Consider the following augmented matrix:
$\left[ \begin{matrix}
1 & -1 & -2 & 2 \\
0 & 1 & -10 & -1 \\
0 & 0 & 0 & 5 \\
\end{matrix} \right]$
The last row, that is, row 3 of the matrix, is expressed in the equation as:
$0x+0y+0z=5$
Since $0\ne 5$, the equation does not make any sense.
Therefore, the system of linear equations has no solution. Hence, row 3 of the above matrix cannot be deleted.
