Answer
a. $y=60+2.8x$
b. $y=44+3.8x$
c. year $ 2014$, $104.8$ thousand
Work Step by Step
a. Based on the given conditions, we can write the function as $y=60+2.8x$
b. Similarly, based on the given conditions, we can write this function as $y=44+3.8x$
c. Letting $60+2.8x=44+3.8x$, we have $x=16$ years, corresponding to year $1998+16=2014$. At $x=16$, we have $y=60+2.8(16)=104.8$ thousand for both models.
