Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.5 - Complex Numbers in Polar Form; DeMoivre's Theorem - Concept and Vocabulary Check - Page 767: 5

Answer

${{r}_{1}}\left( \cos {{\theta }_{1}}+i\sin {{\theta }_{1}} \right).{{r}_{2}}\left( \cos {{\theta }_{2}}+i\sin {{\theta }_{2}} \right)=$ ${{r}_{1}}{{r}_{2}}\left[ \cos \left( {{\theta }_{1}}+{{\theta }_{2}} \right)+i\sin \left( {{\theta }_{1}}+{{\theta }_{2}} \right) \right]$. The product of two complex numbers in polar form is found by multiplying their moduli and adding their arguments.

Work Step by Step

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