Answer
$log_b(\frac{\sqrt x}{x^2+1})$
Work Step by Step
Using logarithmic properties, we have
$\frac{1}{2}log_b(x)-log_b(x^2+1)=log_b(\sqrt x)-log_b(x^2+1)=log_b(\frac{\sqrt x}{x^2+1})$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 6 - Cumulative Review Exercises - Page 801: 18
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