Answer
The amplitude is $4$, period is $1$, and phase shift is $-\frac{1}{\pi }$.
Work Step by Step
The trigonometric expression is
$y=4\sin \left( 2\pi x+2 \right)$
Compare the given equation with $y=A\sin \left( Bx-C \right)$ to get the values of amplitude, period, and phase shift.
Amplitude $\left| A \right|=4$.
And the period can be calculated as follows:
$\begin{align}
& \frac{2\pi }{B}=\frac{2\pi }{2\pi } \\
& =1
\end{align}$
And the value of the phase shift is
$\begin{align}
& \frac{C}{B}=-\frac{2}{2\pi } \\
& =-\frac{1}{\pi }
\end{align}$
