Answer
The statement makes sense.
Work Step by Step
Similarities:
Solve $4x+1=3$ by isolating $x$ on one side of the equation:
$\begin{align}
& 4x+1=3 \\
& 4x=2 \\
& x=\frac{1}{2}
\end{align}$
Isolate the $\sin \theta $ from the equation $4\sin \theta +1=3$
$\begin{align}
& 4\sin \theta =2 \\
& \sin \theta =\frac{1}{2} \\
\end{align}$
Differences:
Isolate the $x$ and solve to get the absolute value for $x$. However, when $\sin \theta $ is isolated, solve for the value of $\theta $ for which $\sin \theta =\frac{1}{2}$; that is, $\sin \theta =\sin \left( \frac{\pi }{6} \right)$ or $\sin \theta =\sin \left( \frac{5\pi }{6} \right)$. So, the values of $\theta $ are $\frac{\pi }{6}$ and $\frac{5\pi }{6}$ between $[0,2\pi )$.
Therefore, the statement makes sense.
