Answer
Identity for $\sin \left( C-D \right)$ is expressed as $\sin C\cos D-\cos C\sin D$.
Work Step by Step
From the difference formula of sines, the sine of the difference between two angles, say A and B, is expressed as,
$\sin \left( A-B \right)=\sin A\cos B-\cos A\sin B$
Thus, for angles C and D,
$\sin \left( C-D \right)=\sin C\cos D-\cos C\sin D$
