Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Review Exercises - Page 709: 63

Answer

$0,\pi$.

Work Step by Step

Step 1. Rewrite the equation as $sin(x)=\frac{sin(x)}{cos(x)}$ or $sin(x)(cos(x)-1)=0$ Step 2. For $sin(x)=0$, we have solutions in $[0,2\pi)$ as $x=0,\pi$ Step 3. For $cos(x)=1$, we have solutions in $[0,2\pi)$ as $x=0$ Step 4. Thus, we have all the solutions in $[0,2\pi)$ as $x=0,\pi$.
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