Answer
Please see below.
Work Step by Step
We verify as follows:
$$\frac{\sec ^2x}{2- \sec ^2 x}=\frac{1}{\frac{2}{\sec ^2 x}-1}=\frac{1}{2\cos ^2 x-1}=\frac{1}{\cos 2x}=\sec 2x$$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 5 - Mid-Chapter Check Point - Page 684: 14
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