Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Test - Page 647: 7

Answer

$\dfrac{1}{2 \sqrt 3}$ or, $\dfrac{\sqrt 3}{6}$

Work Step by Step

Solve. $\tan ( \dfrac{\pi}{6}) \times \cos ( \dfrac{\pi}{3})- \cos \dfrac{\pi}{2} $ $=\dfrac{1}{\sqrt 3} \times \dfrac{1}{2} -0$ $= \dfrac{1}{2 \sqrt 3} \times \dfrac{\sqrt 3}{ \sqrt 3}$ $= \dfrac{\sqrt 3}{6}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.