Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.8 - Applications of Trigonometric Functions - Exercise Set - Page 639: 48

Answer

$80.9^{\circ}$

Work Step by Step

Since, $\tan \theta= \dfrac{height}{Adjacent}$ We can use the tangent of the triangle to solve for the angle. $\tan \theta= \dfrac{250}{40}$ or, $\theta=\tan^{-1} \dfrac{250}{40}$ or, $\theta=80.9^{\circ}$
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