Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.7 - Inverse Trigonometric Functions - Exercise Set - Page 629: 128

Answer

$\approx 35.8^{\circ}$

Work Step by Step

The trigonometric ratios are as follows: $ \tan \theta =\dfrac{height}{hypotenuse}$ or, $ \tan \theta=\dfrac{18}{25} =0.72$ Then $\theta=\tan^{-1} (0.72) \approx 35.8^{\circ}$
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