Answer
Domain : $[-2,0]$ and Range: $[-\dfrac{\pi}{2}, \dfrac{\pi}{2}]$
Work Step by Step
A phase shift of $-1$ results in shifting the domain of the inverse sine curve left by $1$. The range remains the same.
Therefore, we have the Domain and Range of the function as follows:
Domain : $[-2,0]$ and Range: $[-\dfrac{\pi}{2}, \dfrac{\pi}{2}]$
