Answer
Please see below.
Work Step by Step
Please note that a sine function $y=A\sin Bx$ has amplitude $|A|$ and period $\frac{2\pi }{B}$.
So the function $y=3\sin 2\pi x$ has amplitude $|3|=3$ and period $\frac{2\pi }{2\pi }=1$.
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Section 4.5 - Graphs of Sine and Cosine Functions - Exercise Set - Page 595: 12
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