Answer
The statement is true.
Work Step by Step
The above statement can be explained by using the trigonometric identity
$1+{{\tan }^{2}}x={{\sec }^{2}}x$.
After putting the value of $x={{15}^{0}}$ and rearranging the equation, we get:
${{\tan }^{2}}{{15}^{0}}$ $-{{\sec }^{2}}{{15}^{0}}$ is $-1$.
