Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.3 - Right Triangle Trigonometry - Exercise Set - Page 562: 65

Answer

See below.

Work Step by Step

In a right angled triangle, the acute angles are complements. Thus, $\sin (90^{\circ}-\theta) =\cos \theta $ So, the sine of one acute angle is equal to the cosine of the other acute angle.
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