Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.2 - Trigonometric Functions: The Unit Circle - Exercise Set - Page 550: 101

Answer

c

Work Step by Step

Since $\pi \lt t \lt \frac{3\pi }{2}$, the point lies in the third quarter of the unit circle, so we have $\sin t \lt 0$ and $\cos t \lt 0$. Thus,$$\tan t = \frac{\sin t }{\cos t }\gt 0, \qquad \cot t =\frac{\cos t}{\sin t} \gt 0.$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.