Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Mid-Chapter Check Point - Page 578: 28

Answer

$160 \pi =502. 65 feet/ minute $

Work Step by Step

Since, $ s= r \theta $ and $ v=\dfrac{s}{t}$ Here, $\theta =8 (2 \pi)=16 \pi $ and $ r=10$ Thus, we have $ v= \dfrac{r \theta}{t}$ or, $ v= 160 \pi =502. 65 ft/ min $
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