Answer
$2025$
Work Step by Step
Let $f(x)=8$; we have
$\frac{12.57}{1+4.11e^{-0.026x}}=8$
and $4.11e^{-0.026x}=\frac{12.57}{8}-1\approx0.57125$
Thus $t=-\frac{ln(0.57125/4.11)}{0.026}\approx76$, corresponding to year $1949+76=2025$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 3 - Section 3.5 - Exponential Growth and Decay; Modeling Data - Exercise Set - Page 507: 41
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