Answer
The value of the function $\log_b (1)$ is equal to $0$.
Work Step by Step
We have: $ y= \log_a (1)$
The logarithmic equation $ y= \log_a (b)$ when $ x \gt 0$ and $ b \gt 0; b \ne 1$ is equivalent to the exponential form $ a^y=x $, where the logarithmic function $ y $ is the exponent of the exponential function.
Converting our log equation into exponent form, gives:
$ a^y=1$
We know that any positive base to the 0 power is equal to 1. Thus, $y=0$.
Therefore,
$\log_a (1)=0$
