Answer
See graph; asymptotes $y=0$ and $y=1$
Work Step by Step
Step 1. Function $g$ can be obtained by shifting $f$ 1 unit to the right and 1 unit up.
Step 2. Graph both functions $f(x)=(\frac{1}{2})^x$ and $g(x)=(\frac{1}{2})^{x-1}+1$ as shown in the figure.
Step 3. We can identify a horizontal asymptote of $y=0$ for $f(x)$, and $y=1$ for $g(x)$ .
