Answer
The New Year seems to be $\frac{1}{3}rd$ of the original year.
Work Step by Step
Let the year time be $T$ and age be $A$.
Thus,
T=k/A
Now, ${{A}_{1}}=3A$ and the new time ${{T}_{1}}$ is:
$\begin{align}
& {{T}_{1}}=\frac{k}{A_{1}^{{}}} \\
& {{T}_{1}}=\frac{k}{3A} \\
& {{T}_{1}}=\frac{k}{3A} \\
& {{T}_{1}}=\frac{1}{3}T
\end{align}$.
