Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.8 - Modeling Using Variation - Concept and Vocabulary Check - Page 423: 7

Answer

In the equation, $C\ =\ \frac{0.02{{P}_{1}}{{P}_{2}}}{{{d}^{2}}}$ , C varies jointly as ${{P}_{1}}$ and ${{P}_{2}}$ and inversely as the square of d.

Work Step by Step

Let us consider, $C\ =\ \frac{0.02{{P}_{1}}{{P}_{2}}}{{{d}^{2}}}$. It can be seen that when ${{P}_{1}}$ and ${{P}_{2}}$ increase, C also increases or ${{P}_{1}}$ and ${{P}_{2}}$ decrease, S also decreases, and when d increases, C decreases or when d decreases, C increases. Thus here, 0.02 is the constant of proportionality. Thus, in the equation $C\ =\ \frac{0.02{{P}_{1}}{{P}_{2}}}{{{d}^{2}}}$ , C varies jointly as ${{P}_{1}}$ and ${{P}_{2}}$ , and inversely as the square of d.
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