Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.6 - Rational Functions and Their Graphs - Exercise Set - Page 403: 142

Answer

The roots of the polynomial function are $\left\{ -1,\,\,-2,\,\,2 \right\}$.

Work Step by Step

Let us consider the function ${{x}^{3}}+{{x}^{2}}=4x+4$. Simplifying, $\begin{align} & {{x}^{3}}+{{x}^{2}}=4x+4 \\ & {{x}^{3}}+{{x}^{2}}-4x-4=0 \\ & \left( x+1 \right)\left( {{x}^{2}}-4 \right)=0 \\ & \left( x+1 \right)\left( x+2 \right)\left( x-2 \right)=0 \end{align}$ Therefore, $x=-1,\,\,-2,\,\,2$ Hence, the roots are $-1,\,\,-2,\,\,2$
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