Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.4 - Dividing Polynomials; Remainder and Factor Theorems - Exercise Set - Page 364: 41

Answer

$x=-1,2,3$

Work Step by Step

Step 1. The coefficients of the dividend $f(x)$ can be identified in order as $\{1,-4,1,6\}$ and the divisor is $x+1$; use synthetic division as shown in the figure to get the quotient and the remainder. Step 2. We can identify the result as $f(x)=(x^2-5x+6)(x+1)=(x-3)(x-2)(x+1)$; thus we can find the zeros of $f(x)$ as $x=-1,2,3$
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