Answer
The zeros of a polynomial function are defined as the values of x for which $f\left( x \right)$ is equal to $0$. These values of x are the roots or solutions of the polynomial equation, $f\left( x \right)=0$.
Work Step by Step
We know that the zeros of a polynomial function are defined as the values of x for which $f\left( x \right)$ is equal to $0$. These values of x are the roots or solutions of the polynomial equation, $f\left( x \right)=0$.
So, to find zeros of a polynomial function $f\left( x \right)$ , put $f\left( x \right)=0$ and solve for x.
For example, let us consider $f\left( x \right)={{x}^{2}}-16x+48$
Put $f\left( x \right)=0$ ,
$\begin{align}
& {{x}^{2}}-16x+48=0 \\
& ={{x}^{2}}-12x-4x+48 \\
& =x\left( x-12 \right)-4\left( x-12 \right) \\
& =\left( x-4 \right)\left( x-12 \right)
\end{align}$
It will give
$\begin{align}
& x-4=0 \\
& x=4 \\
\end{align}$
And
$\begin{align}
& x-12=0 \\
& x=12 \\
\end{align}$
Thus, $4$ and $12$ are the zeros of $f\left( x \right)$.
