Answer
The factorized form of the given polynomial is $\left( x-1 \right)\left( x+1 \right)\left( x+3 \right)$.
Work Step by Step
Let us consider the given polynomial ${{x}^{3}}+3{{x}^{2}}-x-3$.
Equate the polynomial to 0,
$\begin{align}
& {{x}^{3}}+3{{x}^{2}}-x-3=0 \\
& {{x}^{2}}\left( x+3 \right)-1\left( x+3 \right)=0 \\
& \left( {{x}^{2}}-1 \right)\left( x+3 \right)=0 \\
& \left( x+1 \right)\left( x-1 \right)\left( x+3 \right)=0
\end{align}$
Hence, the polynomial can be expressed as $\left( x-1 \right)\left( x+1 \right)\left( x+3 \right)$.
