Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Review Exercises - Page 431: 50

Answer

$\frac{p}{q}=\pm1,\pm2,\pm4\pm8,\pm\frac{1}{3},\pm\frac{2}{3},\pm\frac{4}{3},\pm\frac{8}{3}$

Work Step by Step

Based on the Rational Zero Theorem, for the given function, we have $p=\pm1,\pm2,\pm4,\pm8$, $q=\pm1,\pm3$, and the possible rational zeros are $\frac{p}{q}=\pm1,\pm2,\pm4\pm8,\pm\frac{1}{3},\pm\frac{2}{3},\pm\frac{4}{3},\pm\frac{8}{3}$
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