Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Mid-Chapter Check Point - Page 381: 1

Answer

The standard form of the expression $\left( 6-2i \right)-\left( 7-i \right)$ is $-1-i$.

Work Step by Step

Consider the expression, $\left( 6-2i \right)-\left( 7-i \right)$ Remove the parentheses. $\left( 6-2i \right)-\left( 7-i \right)=6-2i-7+i$ Combine the real part and the imaginary part. $\begin{align} & \left( 6-2i \right)-\left( 7-i \right)=\left( 6-7 \right)+\left( 1-2 \right)i \\ & =-1-i \end{align}$ Therefore, the standard form of the expression $\left( 6-2i \right)-\left( 7-i \right)$ is $-1-i$.
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