Answer
amplitude $ 2$, period $ \pi$, phase shift $\phi=\frac{\pi}{4}$
Work Step by Step
Step 1. Given $y=2sin(2x-\frac{\pi}{2})=2sin2(x-\frac{\pi}{4})$, we can identify the amplitude as $|A|=2$, period as $p=\frac{2\pi}{2}=\pi$, and phase shift as $\phi=\frac{\pi}{4}$
Step 2. We can graph the function using transformations. From $y=sin(x)$, shift the curve $\frac{\pi}{4}$ to the right, shrink horizontally by a factor of 2, and stretch vertically by a factor of 2. The final graph is shown in the figure.