Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Section 11.1 - Finding Limits Using Tables and Graphs - Exercise Set - Page 1137: 4

Answer

$\lim_\limits{x\to 0}\frac{\sin 4x}{\sin 2x}=2$

Work Step by Step

To find the limit using the table, we must find the value that $f(x)$ approaches, as $x$ approaches a given value. Here, we are asked to find the limit as $x\to0$. As $x$ approaches $0$ from both sides, it is clear that the values of $f(x)$ are approaching $2$. Thus, $\lim_\limits{x\to 0}\frac{\sin 4x}{\sin 2x}=2$.
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