Answer
$210$
Work Step by Step
$^{10}C_{4}=\dfrac{10! }{(10-4)!}$
We know that $ n!=1 \cdot 2 \cdot 3 .....(n-1)n $
Thus, we have $\dfrac{10! }{(10-4)!}$
$= \dfrac{10 \cdot 9\cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1}{6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 \times 2 \cdot 1 }$
$=210$
