Answer
$105$
Work Step by Step
In order to set up the summation notation, we must calculate that value which keeps constantly changing. That value will be designated as the $i$ term. The remaining terms would remain constant in the summation notation.
Thus, we get the summation notation as:
$\sum_{i=1}^{5} (i^2+10)=\sum_{i=1}^{5} (i^2)+\sum_{i=1}^{5} (10)=\sum_{i=1}^{5} (i^2)+10 \times \sum_{i=1}^{5} 1$
Now, $=(1)^2+(2)^2+(3)^2+(4)^2+(5)^2+10(1+1+1+1+1)$
$=105$
