Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.6 - Counting Principles, Permutations, and Combinations - Exercise Set - Page 1104: 41

Answer

The number of different ways in which offices can be filled is 720.

Work Step by Step

The club is choosing 3 officers from a group of 10 members. And the order in which the officers are chosen matters because the president, vice president, and secretary-treasurer each have different responsibilities. Therefore, the number of permutations of 10 things taken 3 at a time needs to be found. By using the formula, ${}_{n}{{P}_{r}}=\frac{n!}{\left( n-r \right)!}$ Where $ n=10,r=3$, $\begin{align} & {}_{10}{{P}_{3}}=\frac{10!}{\left( 10-3 \right)!} \\ & =\frac{10!}{7!} \end{align}$ Solving further, we get: $\begin{align} & _{10}{{P}_{3}}=\frac{10\times 9\times 8\times 7!}{7!} \\ & =10\times 9\times 8 \\ & =720 \end{align}$ Thus, the number of different ways in which the offices can be filled is 720.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.