Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.6 - Counting Principles, Permutations, and Combinations - Exercise Set - Page 1103: 34

Answer

Total number of ways to answer the questions equals to 6561.

Work Step by Step

We know that the situation involves making choices with eight questions. We use the fundamental counting principle to find the number of ways to answer the questions on the test. Multiply the number of choices for each of the eight questions. That is, $\begin{align} & 3\times 3\times 3\times 3\times 3\times 3\times 3\times 3={{3}^{8}} \\ & =6561 \end{align}$ Hence, there are 6561 different ways to answer the questions.
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