Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.6 - Counting Principles, Permutations, and Combinations - Concept and Vocabulary Check - Page 1103: 4

Answer

The number of possible combinations if $r$ objects are taken from $n$ items is $_{n}{{C}_{r}}=$ $\frac{n!}{r!\left( n-r \right)!}$.

Work Step by Step

We know that the combinations of $n$ things taken $r$ at a time can be defined by the formula: ${}_{n}{{C}_{r}}=\frac{n!}{r!\left( n-r \right)!}$ Let us take an example: The combination of 5 things taken 3 at a time is provided by: ${}_{5}{{C}_{3}}=\frac{5!}{3!\left( 5-3 \right)!}$ Thus, the number of possible combinations if $r$ objects are taken from $n$ items is $_{n}{{C}_{r}}=$ $\frac{n!}{r!\left( n-r \right)!}$.
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