Answer
${{k}^{2}}+3k+2=\left( {{k}^{2}}+k \right)+2$ $\left( k+1 \right)$
Work Step by Step
Solving, we get
$\begin{align}
& {{k}^{2}}+3k+2={{k}^{2}}+k+2k+2 \\
& ={{k}^{2}}+k+2\left( k+1 \right) \\
& =\left( {{k}^{2}}+k \right)+2\left( k+1 \right)
\end{align}$
