Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.3 - Geoetric Sequences and Series - Exercise Set - Page 1076: 103

Answer

The statement makes sense.

Work Step by Step

A general term of a geometric sequence is given by: ${{a}_{n}}={{a}_{1}}\times {{r}^{n-1}}$ The exponential function f with base b is defined as below: $f\left( x \right)={{b}^{x}}$ A vertical stretch or shrink of the above exponential function is represented by: $g\left( x \right)=a\times {{b}^{x}}$ Substituting r in place of b and $n-1$ in place of x we get, $g\left( x \right)=a\times {{r}^{n-1}}$ So, if we compare the function $f\left( x \right)$ and $g\left( x \right)$, we can see that both are exponential functions. So, a geometric sequence is an exponential function whose domain is the set of positive integers.
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