Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.3 - Geoetric Sequences and Series - Concept and Vocabulary Check - Page 1073: 8

Answer

$4,8,16,32,64,...$ Geometric

Work Step by Step

After observing the sequence carefully, we can notice that the difference between two consecutive terms is not the same. Thus, the common ratio will be determined as $4,8,16,32,64,...$ Here, ${{a}_{1}}=4,{{a}_{2}}=8,{{a}_{3}}=16,{{a}_{4}}=32,{{a}_{5}}=64,...$ Then, $\begin{align} & \frac{{{a}_{2}}}{{{a}_{1}}}=\frac{8}{4} \\ & =2 \\ & \frac{{{a}_{3}}}{{{a}_{2}}}=\frac{16}{8} \\ & =2 \end{align}$ $\begin{align} & \frac{{{a}_{4}}}{{{a}_{3}}}=\frac{32}{16} \\ & =2 \\ & \frac{{{a}_{5}}}{{{a}_{4}}}=\frac{64}{32} \\ & =2 \end{align}$ Therefore, the common ratio is 2. Hence the sequence is Geometric.
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