Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.2 - Arithmetic Sequences - Exercise Set - Page 1060: 52

Answer

$29$

Work Step by Step

Here, we have $a_{16}=1+(16-1)(-3-1)=-59$ and $b_{18}=3+(18-1)(8-3)=88$ Thus, $a_{16}+b_{18}=-59+88=29$
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