Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.4 - Linear Functions and Slope - Exercise Set - Page 216: 111

Answer

The given statement is true.

Work Step by Step

Consider the given linear equation: \[5x+6y-30=0\] (1) Rearrange the equation (1) in the slope–intercept form:\[y=mx+c\] \[\begin{align} & 5x+6y-30+30=30 \\ & 5x+6y=30 \\ & 5x+6y-5x=30-5x \\ & 6y=30-5x \end{align}\] Dividing both sides by 6 we get, \[\begin{align} & y=\frac{30}{6}-\frac{5}{6}x \\ & =5-\frac{5}{6}x \end{align}\] Rearranging further: \[y=-\frac{5}{6}x+5\] Hence, the slope–intercept form of the given equation is\[y=-\frac{5}{6}x+5\]. Compare this equation to the standard slope intercept form equation of a straight line to get the value of the slope and y intercept. \[\begin{align} & m=\frac{-5}{6} \\ & b=5 \\ \end{align}\] Now, consider the slope–intercept form obtained for the given equation: \[y=-\frac{5}{6}x+5\]
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