Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.4 - Linear Functions and Slope - Exercise Set - Page 214: 87

Answer

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Work Step by Step

(a) Hence, $\begin{align} & m=\frac{47.8-38.9}{30-20} \\ & =0.89 \end{align}$ It is given that the line passes through the points: $\begin{align} & y-{{y}_{1}}=m\left( x-{{x}_{1}} \right) \\ & y-{{y}_{2}}=m\left( x-{{x}_{2}} \right) \end{align}$ Then, $\begin{align} & y-38.9=0.89\left( x-20 \right) \\ & y-47.8=0.89\left( x-30 \right) \end{align}$ Therefore, the equation of the line is $y-38.9=0.89\left( x-20 \right)$ or $y-47.8=0.89\left( x-30 \right)$. (b) Consider the equations, $\begin{align} & y-38.9=0.89\left( x-20 \right) \\ & y=0.89x-17.8+38.9 \\ & y=0.89x+21.1 \end{align}$ Where, $y$ is also a function of $x$. It means we can write $y=f\left( x \right)$. Therefore, the equation of the line by use of function notation is $f\left( x \right)=0.89x+21.1$. (c) Consider the linear function, $f\left( x \right)=0.89x+21.1$ Where, $x$ is the number of years after $1980$ and $f\left( x \right)$ is the percentage of never married American females. In $2020$ , $\begin{align} & x=2020-1980 \\ & =40 \end{align}$ Substitute the value of $x$ in the given equation, $\begin{align} & f\left( x \right)=0.89\cdot 40+21.1 \\ & =56.7 \end{align}$ Therefore, the percentage of never married American females in $2020$ is $56.7\%$.
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