Answer
Refer to the image below for the graph:
Work Step by Step
RECALL:
The point $(x, y)$ has:
$x$ = directed distance of the point from the y-axis (positive when to the right of the y-axis, negative when to the left)
$y$ = directed distance of the point from the x-axis (positive when above the x-axis, negative when below)
Thus, the given point is:
4 units to the left of the y-axis
0 units from the x-axis (which means the point is on the x-axis)
(refer to the attached image in the answer portion for the graph)
