Answer
$(x+2)^2+(y-4)^2=36$
Work Step by Step
Given the center and radius of a circle as $C(-2,4), r=6$, using the standard form of a circle, we can write the equation as $(x+2)^2+(y-4)^2=(6)^2$ or $(x+2)^2+(y-4)^2=36$
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