Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - Chapter Review - Chapter Test - Page 560: 15

Answer

$2.23.$

Work Step by Step

By the law of cosine: $AB^2=a^2+b^2-2ab\cdot \cos{(C)}$. Hence $AB^2=4.2^2+3.5^2-4.2\cdot3.5\cdot \cos{(32^\circ)}\approx4.96$. Thus $AB=\sqrt{4.96}=2.23.$
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