Answer
a)$\frac{\sqrt2}{4}$
b)$\frac{1}{2}$
Work Step by Step
a) $\sin{\frac{\pi}{4}}\cos{\frac{\pi}{3}}=\frac{\sqrt2}{2}\frac{1}{2}=\frac{\sqrt2}{4}$
b) $\tan{\frac{\pi}{4}}-\sin{\frac{\pi}{6}}=1-\frac{1}{2}=\frac{1}{2}$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - 7.5 Sum and Difference Formulas - 7.5 Assess Your Understanding - Page 487: 3
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