Answer
$-\dfrac{\sqrt 3}{3}$
Work Step by Step
We have:
$\tan 330=-\tan 30=-\dfrac{\sqrt 3}{3}$
(we used the reference angle $30$ degrees and the minus sign because $330$ degrees is in Quadrant IV where tangent is negative)
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 6 - Trigonometric Functions - Chapter Review - Chapter Test - Page 436: 10
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