Answer
$1$
Work Step by Step
RECALL:
$\sin ^{2}\alpha +\cos ^{2}\alpha =1$
Therefore,
$\sin ^{2}40^o+\cos ^{2}40^o=1$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding - Page 395: 77
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