Answer
$363$
Work Step by Step
If $N=P(1-e^{-0.15d})$, then if $P=1000$, $d=3$, $N(3)=1000(1-e^{-0.15\cdot3})=362.37\approx363$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - 5.3 Exponential Functions - 5.3 Assess Your Understanding - Page 283: 112
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