Answer
$\frac{1}{2}$, $\frac{3}{4}$, $\frac{2}{3}$, and $0$
Work Step by Step
If $P(E)$ is the probability of the event $E$, then $0\leq P(E)\leq1$.
Hence, here $\frac{1}{2}$, $\frac{3}{4}$, $\frac{2}{3}$, and $0$ are possible values of the probability of an event.